Fill in the missing number

Mathematics

1 answer:

alexandr402 [8]3 years ago

5 0

Is there more to the paper that helps out with this certain problem? If in that case then I might be able to help but if not, this seems like a pattern which is extremely difficult to figure out. Thank You!

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PLEASE HELP AND EXPLAIN! A. y=60x B. y=80x C. y=10x D. y= 6x

Rudik [331]

Answer:

C).

Step-by-step explanation:

One of the points on the graph that the path of bike b crosses is (6,60).

When you divide this to find the unit rate you get 10/1 therefore the equation of bike b= y+10X

8 0

3 years ago

Or the figure shown on the right, find m∠3 and m∠4.

ioda

Answer:

m<3=84

m<4=96

Step-by-step explanation:

180-43-41=96

180-96=84

4 0

3 years ago

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What is the least common denominator for 13/108 and 23/233

Karo-lina-s [1.5K]

The first one stays the same as it does not simplify =108

and the second one is the sames as it does not simplify =233

6 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago

12 divided by -3 is what?

Mamont248 [21]

-4 because when you did use 12 divided by 3 you get four but this is negative so you get a negative answer

4 0

3 years ago

Read 2 more answers