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NemiM [27]
3 years ago
10

Which expression is equivalent to (3a +b)(2a-4b)

Mathematics
1 answer:
Yuki888 [10]3 years ago
7 0

<em><u>The equivalent expression is:</u></em>

(3a +b)(2a-4b) = 6a^2 -10ab -4b^2

<em><u>Solution:</u></em>

Given that,

We have to find the equivalent expression

<em><u>Given expression is:</u></em>

(3a +b)(2a-4b)

Multiply each term in first parenthesis with each term in second parenthesis

\rightarrow (3a +b)(2a-4b) = (3a \times 2a) -(3a \times 4b) + (b \times 2a) -(b \times 4b)\\\\Simplify\ the\ above\\\\\rightarrow (3a +b)(2a-4b) = 6a^2 -12ab + 2ab -4b^2\\\\Combine\ the\ like\ terms\\\\\rightarrow (3a +b)(2a-4b) = 6a^2 -10ab -4b^2

Thus the equivalent expression is found

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What multiplies to -29 and adds to 1
Margarita [4]
First set up equation
x times y=xy

so
xy=-29
and
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subtract x from both sides
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so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so

if
ax+bx+c=0 then x=\frac{ -b+/-\sqrt{b^2-4ac} }{2a} that means x=\frac{ -b-\sqrt{b^2-4ac} }{2a} or x=\frac{ -b-\sqrt{b^2-4ac} }{2a} so


x^2-x-29
a=1
b=-1
c=-29
\frac{ -(-1)-\sqrt{-1^2-4(1)(-29)} }{2(1)}=\frac{ +1-\sqrt{1^2-(-116)} }{2(1)}=\frac{ +1-\sqrt{1^2+116} }{2}=\frac{ +1-\sqrt{117} }{2}= \frac{1-10.816653826392}{2} = [tex] \frac{-9.816653826392}{2}= -4.908326913196



the second number is
\frac{ -(-1)+\sqrt{-1^2-4(1)(-29)} }{2(1)}=\frac{ +1+\sqrt{1^2+(-116)} }{2(1)}= \frac{1+10.816653826392}{2} = \frac{ +1+\sqrt{117} }{2}=  \frac{10.816653826392}{2}=5.908326913196


the two numbers are
5.908326913196 and
-4.908326913196


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