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- First find the area of the whole circle
The equation is :
πr^2
Substitute the radius in:
π(5)^2
Solve:
Area of full circle = 25π
(Note : leave this answer in terms of 'pi' so it is easier to handle
Next, find the area of the sector
The equation for this is:
(angle/360) x πr^2
Substitute the values in:
(80/360) x π(5)^2
Solve :
Area of sector = (50/9)π
Now, find the area of the triangle:
1/2 absinC
Substitute the values in:
1/2(5)(5) x sin(80) = 12.31009691
Subtract this answer from the area of the sector
Answer = 5.14319607
Subtract this from the area of the whole circle
Answer = 73.39662073
To the nearest tenth, that would be 73.4 cm^2
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Answer:
Step-by-step explanation:
Remember, the formulas for the lateral surface area of a pyramid is 12pl and the total surface area is 12pl+B .
Since the base of a cone is a circle, we substitute 2πr for p and πr2 for B where r is the radius of the base of the cylinder.
So, the formula for the lateral surface area of a right cone is L.S.A=πrl , where l is the slant height of the cone.
Find the lateral surface area of a right cone if the radius is 4 cm and the slant height is 5 cm.
L.S.A=π(4)(5)=20π≈62.82 cm2
To graph a piecewise function, simply graph both functions. However, if, for the function it says something like x>0, erase the function for the values of x not greater than 0. The domain is what the x values can be, and the range is what the y values can be.
Answer:
Product of -2 and 5 is -2 times 5, or 5 times -2 (5 * -2).
You can think of this as 5 lots of -2.
If each (-) is a negative,
-2 = (-)(-)
5* -2 =
(-)(-) (-)(-) (-)(-)
(-)(-) (-)(-)
= -10
Step-by-step explanation:
(( I might be wrong- If I am I shall give u a pretty picture~ <3 ))
