Answer:
4
Step-by-step explanation:
![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
= ![\sqrt[3]{4*4*4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%2A4%2A4%7D)
=4
A 0 will make the right decision
If you want to know the concept of square roots and cube roots ?
the square root of a number is that number which when multiplied by itself two times gives us that number
e.g.
√64 = x , so that (x)(x) = 64
and from our multiplication table we know that
(8)(8) = 64 , so that
√64 = 8
the cube root of a number is that number which when multiplied by itself three times gives us that number
e.g.
∛64 = x , so that (x)(x)(x) = 64 , and thus x = 4 because 4x4x4 = 64
so ∛64 = 4
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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