A rocket was launched into the air from a podium 6 feet off the ground. The rocket path is represented by the equation h(t)=-16t ^2+120t+6, where h(t) represents the height, in feet, and t is the time, in seconds. Find the average rate of change from the initial launch to the maximum height.
1 answer:
Answer:
60
Step-by-step explanation:
The given function is:
The average rate of change of h(t) from t=a to t=b is given by:
We can rewrite this function as:
The maximum height of the rocket is 231 and it occurs at t=3.75
The initial launch occurs at: t=0
and
The average rate of change from the initial launch to the maximum height is
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