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Natalka [10]
3 years ago
15

What is the list price 45 off 1/4

Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0
34 is your answer hope it helps
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A model rocket is launched with an initial velocity of 250 ft per second. The height h, in feet, of the rocket t seconds after t
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9514 1404 393

Answer:

  {2.96, 12.66}

Step-by-step explanation:

A graph shows the rocket will be 600 feet up after 2.96 seconds, and again at 12.66 seconds.

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You can solve the equation h = 600 to find the times.

  -16t^2 +250t = 600

  -16(t^2 -15.625t) = 600

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The rocket will be 600 ft above the ground 2.96 and 12.66 seconds after launch.

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I^2 = -1
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