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Lubov Fominskaja [6]
3 years ago
13

James has 12 dimes in hus pocket.How much money does he have

Mathematics
2 answers:
Scrat [10]3 years ago
5 0

Hello, the answer is $ 1.20 because.

1 dime = 10 cents

so 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. = 1.00 then 2 more dimes left

10, 20. so $ 1.20.

Have a good day! mark brainliest please.

Alex73 [517]3 years ago
4 0

Answer:

one dollar and twenty cents

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If a and b are positive numbers, find the maximum value of f(x) = x^a(2 − x)^b on the interval 0 ≤ x ≤ 2.
Ad libitum [116K]

Answer:

The maximum value of f(x) occurs at:

\displaystyle x = \frac{2a}{a+b}

And is given by:

\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

Step-by-step explanation:

Answer:

Step-by-step explanation:

We are given the function:

\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0

And we want to find the maximum value of f(x) on the interval [0, 2].

First, let's evaluate the endpoints of the interval:

\displaystyle f(0) = (0)^a(2-(0))^b = 0

And:

\displaystyle f(2) = (2)^a(2-(2))^b = 0

Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:

\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right]

By the Product Rule:

\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}

Set the derivative equal to zero and solve for <em>x: </em>

\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right]

By the Zero Product Property:

\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0

The solutions to the first equation are <em>x</em> = 0 and <em>x</em> = 2.

First, for the second equation, note that it is undefined when <em>x</em> = 0 and <em>x</em> = 2.

To solve for <em>x</em>, we can multiply both sides by the denominators.

\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))

Simplify:

\displaystyle a(2-x) - b(x) = 0

And solve for <em>x: </em>

\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\  \frac{2a}{a+b} &= x  \end{aligned}

So, our critical points are:

\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}

We already know that f(0) = f(2) = 0.

For the third point, we can see that:

\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b

This can be simplified to:

\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

Since <em>a</em> and <em>b</em> > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.

To confirm that this is indeed a maximum, we can select values to test. Let <em>a</em> = 2 and <em>b</em> = 3. Then:

\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)

The critical point will be at:

\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8

Testing <em>x</em> = 0.5 and <em>x</em> = 1 yields that:

\displaystyle f'(0.5) >0\text{ and } f'(1)

Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.

Therefore, the maximum value of f(x) occurs at:

\displaystyle x = \frac{2a}{a+b}

And is given by:

\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b

5 0
3 years ago
What two numbers are located 1/2 of a unit from 1/6 on a number line?
ella [17]

Answer:

2/3 and -1/3

Step-by-step explanation:

We have to find which two numbers on the number line are at a distance of 1/2 from 1/6.

The two numbers that are 1/2 units away from 1/6 will be:

1) \frac{1}{6}+\frac{1}{2}\\\\ =\frac{1}{6}+\frac{3}{6}\\\\ =\frac{4}{6}\\\\=\frac{2}{3}

2) \frac{1}{6}-\frac{1}{2}\\\\ =\frac{1}{6}-\frac{3}{6}\\\\ =\frac{-2}{6}\\\\ =\frac{-1}{3}

Thus the two numbers are: 2/3 and -1/3

8 0
3 years ago
Read 2 more answers
??? times 4/9 is negative 8
Nitella [24]
-2/9 x 4/9 is -8
so the answer is -2/9
5 0
3 years ago
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The cost C (in dollars) of producing x DVD players is represented by C = 4.5x2. How many DVD players are produced if the cost is
lisabon 2012 [21]

Given the following equation representing the cost of producing DVD Players:

\text{ C = 4.5x}^2

Let's determine the number of DVD players produced if the cost is $544.50

\text{ C = 4.5x}^2\text{ \$544.50 = 4.5x}^2\text{ }\frac{\text{\$544.50}}{\text{ 4.5}}\text{ = }\frac{\text{4.5x}^2}{\text{ 4.5}}\text{ 121 = x}^2\text{ }\sqrt{\text{121}}\text{ = }\sqrt{\text{x}^2}\text{ 11 = x}

Therefore, it'll cost $544.50 to produce 11 DVD Players.

The answer is 11.

3 0
1 year ago
Marks lawn care company charges a flat fee of $15, plus $9 per half hour for every job. which equation can be used to find the a
Sedaia [141]

Answer:

y= 18x + 15

Step-by-step explanation:

If its 9 dollars per hour than it would be 18 per hour. The independent variable is the how long itll take, and the 15 would be without starting. So it results into B) y=18x+15

3 0
3 years ago
Read 2 more answers
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