Question

Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. How many units below the y-intercept of g(x) is the y-intercept of f(x)?

Answer 1

Answer:

The distance between y-intercepts of f(x) and g(x) = 3 units

Step-by-step explanation:

For better understanding of the solution, see the plotted graph which is attached below :

f(x) = x - 1

g(x) = x + 2

Now, to find the distance between the y - intercepts of f(x) and g(x), First find the y-intercepts of both the given functions

y-intercepts of f(x) = x - 1

At y-intercept the x-coordinate = 0

⇒ y = 0 - 1

⇒ y = -1

y-intercepts of g(x) = x + 2

At y-intercept the x-coordinate = 0

⇒ y = 0 + 2

⇒ y = 2

Now, distance between the two intercepts = 2 - (-1)

                                                                        = 2 + 1

                                                                        = 3

Hence, the distance between y-intercepts of f(x) and g(x) = 3 units

Answer 2

These functions are in the form y=mx+b
Therefore, we know that in g(x) = x+2, the y-intercept is 2. 
For f(x) = x-1, the y-intercept is -1. 
Now find the difference between them. 
2-(-1)= 3
The y-intercept for f(x) is 3 units below g(x)