Would love to help but unsure what you are referring too
I think the answer could be 10 or even 12
Standard form is, hold a sec
x=2 is directix
that means it opens left or right
so we must use
(y-k)²=4p(x-h)
where vertex is (h,k) and p is distance from focus to vertex
also shortest distance from vertex to directix
the shortest distance from focus to directix is 2p
if p>0 then the parabola opens right
if p<0 then pareabola opens left
so
(-2,0) and x=2
the distance is 4
4/2=2
p=2
wait, positive or negative
focus is to the left of the directix so p is negative
p=-2
vertex is 2 to the right of the focus and 2 to the left of directix
vertex is (0,0)
so
(y-0)²=4(-2)(x-0) or
y²=-8x is da equation
not sure what form is standard tho
To find the x-intercept, you need to set y equal to zero(think about this on a graph!)
This will become:
x + 2(0) = 8
If we remove the unnecessary zero:
x = 8
That's the x intercept, which can be expressed as the point (8,0).
To find the y-intercept, you need to set x equal to zero(again, think about that on a graph!)
This becomes:
0 + 2y = 8
Remove the unnecessary 0:
2y = 8
Divide both sides by 2:
y = 4
There ya go! Or, in point form: (0, 4)
Hope this helped! :)
~Chrys
There is not enough detail for me to answer
