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Ket [755]
3 years ago
5

A car travels east at 35 mi/h through a wind that is moving north at a rate of 10 mi/h. To the

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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If Sn=2^n-1<br><br>what's the expression of<br>Sn-1?​
Naya [18.7K]

Answer:

S(n-1)=2^{n-2}

Step-by-step explanation:

Given that,

The value of S_n=2^{n-1}

We need to find an expression for S(n-1). To find it, put the value of n as (n-1). So,

S_{n-1}=2^{n-1-1}\\\\=2^{n-2}

Hence, the value of S(n-1) is equal to 2^{n-2}.

4 0
3 years ago
In 3 hours, a car travels 120 miles. What is the speed of the car
ludmilkaskok [199]
120/3=40
40 miles an hour
3 0
3 years ago
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The perimeter of a right triangle is 24 ft, and one of its legs measures 6 ft. Find the length of the other leg and the hypotenu
Mrrafil [7]

Answer:

Step-by-step explanation:

We know the perimeter of a triangle is the sum of all the sides( two legs and one hypotenuse).

By pythagoras we know that

h^2= a^2+b^2.

and the perimeter is P=h+a+b.

Since P=24 and a=6  we have these equations:

h^2=36+b^2\\24=h+6+b

From the last equation we have h=18-b. Replace h in the first equation we get that

(18-b)^2=36+b^2

18^2-36b+b^2=36+b^2\\288=36b\\b=\frac{288}{36}=8

and h=18-8=10

5 0
3 years ago
How many kilograms are in 5500 g? Show all work
podryga [215]
5.5, divide 5,500 by 1,000 to get 5.5 kg.
3 0
4 years ago
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A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these
Vinvika [58]

Answer:

133 fishes

Step-by-step explanation:

Units of food A = 400 units

Units of food B = 400 units

Fish Bass required 2 units of A and 4 units of B.

Fish Trout requires 5 units of A and 2 units of B.

i. For food A,

total units of food A required = 2 + 5

                                                 = 7 units

number of bass and trout that would consume food A = 2 x \frac{400}{7}

                                               = 114.3

number of bass and trout that would consume food A = 114

ii. For food B,

total units of food B required = 4 + 2

                                                = 6 units

number of bass and trout that would consume food B = 2 x \frac{400}{6}

                                                 = 133.3

number of bass and trout that would consume food B = 133

Thus, the maximum number of fish that the lake can support is 133.

4 0
3 years ago
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