Answer:
Step-by-step explanation:
The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation 
, where we will use ft for distances.
From the given equation we have then 
, which means 
since the arcsin is the inverse function of the sin.
Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have 
, and from now on we have just to use a calculator, obtaining 
The original price was $142.50. What I did was that I added 40% with $101.79 which was the sales price. With the 40% the person saved $40.71.
Hope this helps : )*****
Answer:
This is a bit confusing for me but here we go.
1x110
10x11 and
i don't really know the third
Step-by-step explanation:
Answer:
Option C. 12 by 15
Step-by-step explanation:
Let the length be L
Let the width be w
Area of rectangle = L x w
Perimeter of rectangular = 2 (L + w)
From the question given,
A = 180
P = 54
180 = L x w (1)
54 = 2(L + w) (2)
From equation (2),
54 = 2(L + w)
Divide both side by the 2
54/2 = L + w
27 = L + w
L = 27 — w (3)
Substituting the value of L into equation (1), we have:
180 = L x w
180 = w(27 — w)
180 = 27w — w^2
Rearrange the expression
w^2 — 27w + 180 = 0 (4)
Solving by factorization method:
Multiply the first term (i.e w^2) with the last term (i.e 180). This gives 180w^2. Now find two factors of 180w^2, such that their sum will result to the second (i.e —27w). These factors are —12w and —15w.
Now, substitute these factors (—12w and —15w) into equation (4)
w^2 — 27w + 180 = 0
w^2 — 12w —15w + 180 = 0
w(w — 12) — 15(w — 12) =0
(w — 12) (w — 15) = 0
w = 12 or w = 15.
Substituting the value of w into equation (3)
L = 27 — w
When w = 12
L = 27 — 12 = 15
When w = 15
L = 27 — 15 = 12
Since the length is longer than the width, the length is 15 and the width is 12.
Therefore the dimensions is 12 x 15
