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UNO [17]
3 years ago
9

Solve for Q Q/B + A = Y

Mathematics
1 answer:
Otrada [13]3 years ago
6 0
What are the numbers that are supposed to be plugged in?

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Nate is 4 years older than 2 times his brother’s age. Write a rule that represents Nate’s age “n” as a function of his brother’s
IRINA_888 [86]

Answer:

n = 2b + 4

Step-by-step explanation:

4 years older = +4

2 times his brother = 2b

n= 2b+4

6 0
3 years ago
Write 0.1 as a percentage
4vir4ik [10]
To write 0.1 as a percentage you have to multiply it by 100 and then put the % sign at the end of it.

0.1 X 100 = 10%
5 0
3 years ago
1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp
Andrei [34K]

Answer:  see below

<u>Step-by-step explanation:</u>

1) Foci is plural for Focus.  Since a hyperbola has two focus points, they are referred to as foci.  The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

    a)  does the hyperbola open up or to the right?

    b)  what is the center (h, k) of the hyperbola?

    c)  What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1

  • (h, k) is the center of the hyperbola
  • ± b/a is the slope of the line of the asymptotes
  • The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0
3 years ago
How do u simplify 3/30​
sukhopar [10]

\bf \cfrac{3}{30}\implies \cfrac{3\cdot 1}{3\cdot 10}\implies \cfrac{3}{3}\cdot \cfrac{1}{10}\implies 1\cdot \cfrac{1}{10}\implies \cfrac{1}{10}

8 0
3 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
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