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Ghella [55]
3 years ago
11

Dora’s register shows an automatic payment on 10/4 in the amount of $452.17, an ATM withdrawal on 10/5 in the amount of $120.00,

and a deposit on 10/9 in the amount of $510.11.
What should the balance be in Dora’s register? Use this bank statement.
A bank statement showing deductions and a deposit


A. $679.99

B. $663.92

C. $542.45

D. $525.85
Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

It's C. 542.45

Step-by-step explanation:

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Which shows all the like terms in the expression? <br> 4x-3+7x+1<br> (variables are X)
wlad13 [49]

Answer:

11x-2

Step-by-step explanation:

We have been given an expression 4x-3+7x+1. We are supposed to combine like terms for our given expression.

We can see that 4x\text{ and }7x are like terms as both of these terms have x variable.

Similarly, -3\text{ and }1 are like terms as both are constant.

Upon combining like terms, we will get:

4x+7x-3+1

11x-2

Therefore, our required expression would be 11x-2.

6 0
3 years ago
How many positive integers between 5 and 31
Anestetic [448]

Answer:

Part (A): There are 9 integers between 5 and 31 which are divisible by 3.

Part (B): There are 6 integers between 5 and 31 which are divisible by 4.

Part (C): There are 2 integers between 5 and 31 which are divisible by 3 and by 4.

Step-by-step explanation:

Consider the provided information.

Part (A) we need to find how many integers between 5 and 31 are divisible by 3.

Between 5 and 31 there are 25 integers.

According to quotient rule: \frac{25}{3} \approx8.33

That means either 8 or 9 integers are divisible by 3 as 8.33 lies between 8 and 9.

The integers are: 6, 9, 12, 15, 18, 21, 24, 27, 30

Hence, there are 9 integers between 5 and 31 which are divisible by 3.

Part (B) we need to find how many integers between 5 and 31  are divisible by 4.

Between 5 and 31 there are 25 integers.

According to quotient rule: \frac{25}{4} \approx6.25

That means either 6 or 7 integers are divisible by 4, as 6.25 lies between 6 and 7.

The integers are: 8, 12, 16, 20, 24, 28

Hence, there are 6 integers between 5 and 31 which are divisible by 4.

Part (C) we need to find how many integers between 5 and 31 are divisible by 3 and by 4

Between 5 and 31 there are 25 integers.

Integers should be divisible by 3 and by 4, that means integers should be divisible by 3×4=12.

According to quotient rule: \frac{25}{12} \approx2.08

That means either 2 or 3 integers are divisible by 3 and by 4 or 12, as 2.08 lies between 2 and 3.

The integers are: 12, 24,

Hence, there are 2 integers between 5 and 31 which are divisible by 3 and by 4.

7 0
3 years ago
He equation sin (40 degree) equals StartFraction b Over 20 EndFraction can be used to determine the length of line segment AC.
Alisiya [41]

Answer:

The value of b is 12.9 cm

The value of a is 15.3 cm

Step-by-step explanation:

see the attached figure to better understand the problem

<em>Find the value of b</em>

we know that

in the right triangle ABC

The function sine of angle of 40 degrees is equal to divide the opposite side to the angle of 40 degrees (AC) by the hypotenuse (AB)

so

sin(40\°)=AC/AB

Solve for AC

AC=(AB)sin(40\°)

substitute the given value

AC=(20)sin(40\°)

AC=12.9\ cm

therefore

The value of b is 12.9 cm

<em>Find the value of a</em>

we know that

in the right triangle ABC

The function cosine of angle of 40 degrees is equal to divide the adjacent side to the angle of 40 degrees (BC) by the hypotenuse (AB)

so

cos(40\°)=BC/AB

Solve for BC

BC=(AB)cos(40\°)

substitute the given value

BC=(20)cos(40\°)

BC=15.3\ cm

therefore

The value of a is 15.3 cm

3 0
3 years ago
Read 2 more answers
The table below shows the illuminated percentage of the moon on a lunar cycle of 28 days. The relationship can be described usin
pychu [463]

Answer:

StartSet (negative 8, negative 2), (negative 4, 1), (0, negative 2), (2, 3), (4, negative 4) EndSet

Step-by-step explanation:

The function is when there are sets of input and output values given and each input value hem has one corresponding output. Input values are unique but output values can be same for more than one input value.

A.........................................

A 2-column table with 5 rows. The first column is labeled x with entries negative 5, negative 3, negative 3, 0, 5. The second column is labeled y with entries 10, 5, 4, 0, negative 10.

Not a function as input values repeated: negative 3

B.........................................

StartSet (negative 8, negative 2), (negative 4, 1), (0, negative 2), (2, 3), (4, negative 4) EndSet

Yes, it is a function

C.........................................

A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 0, 1. The second column is labeled y with entries negative 3, negative 2, negative 1, 0, negative 1.

Not a function as input values repeated: 0

D.........................................

StartSet (negative 12, 4), (negative 6, 10), (negative 4, 15), (negative 8, 18), (negative 12, 24) EndSet

Not a function as input values repeated: negative 12

So correct one is option B

4 0
3 years ago
Read 2 more answers
A certain arithmetic sequence has the recursive formula an = an-1 + d. If the common difference between the terms of the sequenc
Lady bird [3.3K]
In an Arithmetic sequence, each term is obtained by adding the common difference in the previous term as shown in the recursive formula.

The common difference of the sequence is -13. This means, if we -13 to a term we'll obtain the next term.

If a term is 13, the term that will be next to 13 can be obtained by adding -13 to it.

So, 

13 + ( -13) = 13 - 13 = 0

Thus, the next term will be 0.
7 0
3 years ago
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