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notsponge [240]
3 years ago
8

The boys combine their cans and take them to the local recycling center at the end of the three months. If the recycling center

pays $ 0.40 per pound for aluminum, how much money will Weston and Zachary earn?
Mathematics
2 answers:
erica [24]3 years ago
6 0

Answer:

nothing CUZ YOU DIDNT SAY HOW MUCH THEY BROUGHT if you say that ill answer with the correct answer

Step-by-step explanation:

Olin [163]3 years ago
3 0
Maybe nothing I’m not sure
You might be interested in
Find the perimeter of the figure shown to the right.
tia_tia [17]

Step-by-step explanation:

that is very simple. you do understand the word "perimeter" ? it just means the distance when walking around the whole shape once.

and that clearly means to just add all side lengths.

that's it.

so, 25 + 18 + 18 + 20 + 17 = 98 ft

was there any other problem with this you did not understand ?

8 0
2 years ago
If a+b=9 and ab=18,find the value of a and b.
Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

:)

3 0
3 years ago
Product A is a 12-ounce bottle of generic mouthwash that sells for $1.15. Product B is a 24-ounce bottle of mouthwash that costs
adoni [48]
12 oz = 1.15
24 oz = 2.79
Let's see if 2x12oz is equal, less, or more than the 24oz.
1.15 x 2 = 2.30
2.30<2.79
The 12 oz is a better buy.
3 0
3 years ago
Plz help geometry will mark brainliest
stellarik [79]
15+16+10 =41
BH= 41
Bd=15
Df=16
Fh=10

Plz mark me brainalist answer
3 0
3 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
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