Answer:
cosФ =
, sinФ =
, tanФ = -8, secФ =
, cscФ =
, cotФ = 
Step-by-step explanation:
If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:
- cosФ =

- sinФ =

- tanФ =

- secФ =

- cscФ =

- cotФ =

- Where r =
(the length of the terminal side from the origin to point (x, y)
- You should find the quadrant of (x, y) to adjust the sign of each function
∵ Point (1, -8) lies on the terminal side of angle Ф in standard position
∵ x is positive and y is negative
→ That means the point lies on the 4th quadrant
∴ Angle Ф is on the 4th quadrant
∵ In the 4th quadrant cosФ and secФ only have positive values
∴ sinФ, secФ, tanФ, and cotФ have negative values
→ let us find r
∵ r = 
∵ x = 1 and y = -8
∴ r = 
→ Use the rules above to find the six trigonometric functions of Ф
∵ cosФ = 
∴ cosФ =
∵ sinФ = 
∴ sinФ = 
∵ tanФ = 
∴ tanФ =
= -8
∵ secФ = 
∴ secФ =
= 
∵ cscФ = 
∴ cscФ = 
∵ cotФ = 
∴ cotФ =
Answer:
14
Step-by-step explanation:
its an formula which comes in algebraic expression
Here’s the correct answer and how I got the answer :)
Since it’s a square all sides are even. Meaning you multiply 7/12 by 4. Giving you 7/3 or 2 ⅓. Hope this helps!