Answer:
Marco will need 
of material to make the kite
Step-by-step explanation:
we know that
To know how much material Marco will need to make the kite, the area must be calculated.
Remember that the area of the kite is equal to
![A=\frac{1}{2}[d1*d2]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5Bd1%2Ad2%5D)
where
d1 and d2 are the diagonals of the kite
we have
substitute
![A=\frac{1}{2}[2*3]=3\ ft^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B2%2A3%5D%3D3%5C%20ft%5E%7B2%7D)
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5 where T(1)=11
T(9)=6(9)+5=59
If I'm understanding this correctly:
Tiger consumes 18lb/day of food. If we want to calculate how much is consumed in 28 days, assuming that rate is consistent, the answer is 18*28 = 504lb of food.
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
C= 7.6761229314
Step-by-step explanation:
the formula is c=d/p
d= 324.7
p= 42.3
so ... this is how to calculate...
C = 324.7 km/ 42.3 litres
I hope it can help. thanks
