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MrRissso [65]
2 years ago
12

10x is greater than or equal to 120 cm^2

Mathematics
1 answer:
Agata [3.3K]2 years ago
8 0

Answer:

x greater than or equal to 12cm^2

Step-by-step explanation:

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The number of students attending summer school at a local community college has been decreasing each year by 7%. If 847 students
alina1380 [7]

Answer:

≈ 634

Step-by-step explanation:

n = 847(1 * .07)^4

n = 847(0.93)^4

n = 633.60005247

n ≈ 634

3 0
2 years ago
Help solving one more question please!Mason spent $15.85 for 3 notebooks and 2 boxes of markers.The boxes of markers cost $3.95
inn [45]
Each notebook would be 68 cents because if you divide 15.85 into 3 you will get 2 cents then you add 1.23 then subtract .75
7 0
3 years ago
It's a little blurry sorry please help
Ghella [55]

<u>Answer:</u>

It's X=2

<u>Working out:</u>

<u>(left one):</u>

2(x+3)=10

2x+6=10

2x=10-6

2x=4

x=2

Working out:

(right one):

2(x+3) must be all divided by 2 so it will be x+3 and same for 10, it will be 5 so...

x+3=5

x=5-3

x=2

Hope it helps ^---^

3 0
2 years ago
Read 2 more answers
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
Can anyone help solve this for me ASAP. Thanks!
Anuta_ua [19.1K]

Answer:

x = 20

y = 26

Step-by-step explanation:

40 and 2x are vertical angles, so they're equal to each other.

40 = 2x

Divide both sides by 2

x = 20

We see that 40 and 5y + 10 are a linear pair, which means they add up to 180.

5y + 10 + 40 = 180

5y + 50 = 180

5y = 130

y = 26

8 0
2 years ago
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