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saveliy_v [14]
3 years ago
14

Solve h = −16t2 + 36t + 4.

Mathematics
1 answer:
kvasek [131]3 years ago
5 0
I can do each of the things I asked above.
So, let's change this into vertex form:
h=-16t^2+36t+4
h=(-16t^2+36t)+4
h=-16(t^2-2.25t)+4
h=-16(t^2-2.25t+1.27-1.27)+4
h=-16(t^2-2.25t+1.27)+20.32+4
h=-16(t-1.125)^2+24.32
The vertex is at (1.125,24.32)
<span>Answers may vary due to rounding

</span>Factored Form:
h = -16t^2 + 36t + 4
h = -4\left(4t^2-9t-1\right)

Quadratic Formula:
x =  \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}
<span>h = -16t^2 + 36t + 4
</span>a = -16 b = 36 c = 4
h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}
h = \frac{-36 +/- \sqrt{1552}}{-32}
h = ≈-0.11
h = ≈2.36

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Part A: Factor 2x2c2 + 3xc2 − 35c2. Show your work. (4 points)
Debora [2.8K]

Answer:

a: 12

B: 5  

c: 15

Step-by-step explanation: because you have to multiply and divide but i might have the wrong answerr :((((


3 0
3 years ago
The area of a triangle is 1440cm^2 the base of tge triangle is 5 times the height of the triangle
Oduvanchick [21]
What should we find...
Probably base and the height...

Area = 1440cm²

base = 5×height

base = 5h

Area of triangle = base × height

1440 = 1/2 × 5h × h

1440 = 5h²/2

5h² = 2880

h² = 2880/5

h² = 576

h=24cm..

Height = 24cm

Since base = 5h

Base = 5×24

Base = 120cm...

Hope this helped....

Base =
4 0
3 years ago
What is the coefficient of x5y5 in the expansion of (x + y)10?
butalik [34]

Answer:

C=252

Step-by-step explanation:

Given:

x^5y^5

(x+y)^10

Find the coefficient of x^5y^5

To get the coefficient of x^5y^5,

we will put r = 5, in the below given general term.

The general term is : nCr =x^ry^n-r

We get:

Coefficient is = 10C5

= 10!/5!*5!

= 252

The coefficient of x^5y^5 is 252

C. 252

4 0
2 years ago
Read 2 more answers
Which of the following are solutions to |x-1| = 5X+2
musickatia [10]

Answer:

i can't see the solution options but i got x = -3/4 and x = -1/6

Step-by-step explanation:

4 0
3 years ago
What is the solution to the system of equations????
prohojiy [21]
First of all, we can solve this by elimination (adding the 2 equations and eliminating 1 variable).
3x+10y=-47
5x+7y=40
It looks like we can eliminate the x by making one 15x, and the other -15x (15 is the least common multiple [LCM] of 3 and 5).
5 (3x+10y=-47) --> 15x+50y=-235
-3 (5x+7y=40) --> -15x-21y=-120
15x-15x = 0, 50y-21y = 29y, -235-120 = -355
0 + 29y = -355
29y/29 = -355/29
y = 12.24
then plugged that into 3x+10y=-47
3x+122.4=-47
3x+122.4-122.4=-47-122.4
3x = -169.4
x = 56.47
Something is wrong... are you sure the 2nd equation wasn't equal to NEGATIVE 40??
Or the 1st one equal to POSITIVE 40??
3 0
3 years ago
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