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Ganezh [65]
2 years ago
9

Three circular arcs of radius units bound the region shown. Arcs and are quarter-circles, and arc is a semicircle. What is the a

rea, in square units, of the region?.
Mathematics
1 answer:
mestny [16]2 years ago
8 0

Answer:

Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.

Step-by-step explanation:

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82 less than r is less than -164
Oliga [24]

Answer:

82<r<-164

Step-by-step explanation:

We need to form an inequality of the given statement.

82 less than r is less than -164

Less than is written as <.

82 less than r means, 82<r

r is less than -164, r<-164

Combining two statements,

82<r<-164

Hence, the expression for 82 less than r is less than -164 is 82<r<-164.

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3 years ago
A farmer mows 1/5 of an acre each day. If his property has 3 acres, how many days will it take to mow it all?
solong [7]
15 days


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3 years ago
Garnishment is when finance charges are added to your credit card account when the bill is unpaid. true or false
Anna007 [38]
False...garnishment is when they deduct money directly out of ur account
7 0
3 years ago
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What is four hundred eight thousand,seventeen in standard form and expanded form?
mestny [16]
408,017 is in standard form and
400,000+8,000+10+7=408,017 is expanded form
sixty five thousand and fifty eight is word form
60,000+5,000+50+8=65͵058 is expanded form
6 0
4 years ago
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The water level of a certain body of water is changing at a rate of W(t)=3/4cos(4-t/2) inches per hour, where t represents hours
Leni [432]

Answer:

The answer is below

Step-by-step explanation:

a) The integral \int\limits^{10}_{1 } {W(t)} \, dt means the total change in level of water in inches from 1 am to 10 am. That is the water level change measured in inches between 1 am and 10 am

b) 7 pm is represented as t = 19 hours, while midnight is represented as t = 24 hours, hence the water level change between 7 pm and midnight is:

\int\limits^{24}_{19 } {W(t)} \, dt\\\\

c) Using casio calculator to evaluate the integral gives:

\int\limits^{24}_{19 } {W(t)} \, dt\\\\ = 2.54 inches

D) The total daily change in water level = \int\limits^{24}_{0 } {W(t)} \, dt\\\\ = 0.35 inches

8 0
3 years ago
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