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3 years ago

Someone please help!

Mathematics

1 answer:

strojnjashka [21]3 years ago

8 0

Answer:

37.5°
65°
90°
28

Step-by-step explanation:

1. PB is a bisector of ∠ABC, so ∠PBC is 75°/2 = 37.5°.

2. The sum of angles of ΔABC is 180°, so 75° + 40° +∠CAB = 180°. Subtracting 115° from this equation tells you ...

∠CAB = 65°

3. BQ is an altitude of ΔABC, so ∠BQA = 90°. (An altitude always meets the opposite side at a right angle.)

4. BR = RC

2y +8 = 7y -7

15 = 5y . . . . . add 7-2y

3 = y . . . . . . . divide by 5

BC = BR +RC = (2y +8) +(7y -7) = 9y +1 = 9·3 +1 = 28

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