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prisoha [69]
3 years ago
7

How do I solve this 2(4x^3+9m+3x^2)

Mathematics
1 answer:
S_A_V [24]3 years ago
8 0
2(4x³ + 9m + 3x²)
2(4x³) + 2(9m) + 2(3x²)
8x³ + 18m + 6x²
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23854 miles rounded to the nearest hundred mile
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This would equal about 23,900
i hope this helps you.
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7 0
3 years ago
The population growth of a certain city is given by the function P(t) = 0.9(1.5)^t, where t is time in years. Estimate lim P(t),
gizmo_the_mogwai [7]

Answer:

Infinity (∞)

Step-by-step explanation:

Graph the function and observe that the function P(t) increases without bound as x increases.

6 0
3 years ago
The extract of a plant native to Taiwan has been tested as apossible treatment for Leukemia. One of the chemical compoundsproduc
Gala2k [10]

Answer:

1. P(X>69)=P(Z>-1.136)=1-P(Z

2. P(X

3. P(52.6 \leq X \leq 105.4)=P(-3

Step-by-step explanation:

Assuming the value for the mean 79 and the deviation 8.8

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the amount of collagen of a population, and for this case we know the distribution for X is given by:

X \sim N(79,8.8)  

Where \mu=79 and \sigma=8.8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z-1.136)

And we can find this probability on this way:

P(Z>-1.136)=1-P(Z

3) Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability on this way:

P(Z

4) Part c

We need to find first the limits for 3 deviations within the mean

\mu -3 \sigma = 79-3(8.8)=52.6

\mu +3 \sigma = 79+3(8.8)=105.4

P(52.6

And we can find this probability on this way:

P(-3

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-3

4 0
3 years ago
What is the domain of the relation {(1,-5), (2,3), (-6, -1), (2, 3), (-7, 8), (2, 3)}?
Papessa [141]

Answer:

all work is pictured and shown

8 0
3 years ago
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