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11Alexandr11 [23.1K]
3 years ago
11

What is the inverse of the function f(x) = 8x+1

Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

f⁻¹(x) = (x - 1)/8

Or

f⁻¹(x) = 1/8 x - 1/8

Step-by-step explanation:

To find the inverse of a function, switch the "x" and "y" variables, then isolate "y".

Remember <u>"f(x)" is the same thing as "y"</u>. Change from function notation to "y".

f(x) = 8x + 1

y = 8x + 1        

<u>Switch the "x" and "y" variables</u>

x = 8y + 1

<u>Isolate "y"</u>. Move the "y" variable to the left for standard formatting

8y + 1 = x            

8y + 1 - 1 = x - 1               Subtract 1 from both sides

8y = x - 1

\frac{8y}{8}=\frac{x-1}{8}        Divide both sides by 8 and simplify

y=\frac{x-1}{8}                  Inverse equation

y=\frac{1}{8}x-\frac{1}{8}             Slope-intercept form

<u>Use function notation</u>, change "y"

f^{-1}(x)=\frac{x-1}{8}                      Simplified

f^{-1}(x)=\frac{1}{8}x-\frac{1}{8}                   Slope-intercept form

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