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UkoKoshka [18]
3 years ago
6

Nam has a beginning balance of $815 in her checking account. She writes a check for $210 and has a debit transaction of $525. Wh

at is her new balance?
$125

$80

$1550

$120
Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:the answer is ($80)

Step-by-step explanation:i took the test on k12 online school

plz give me bianleast it helps oh lot thank you

m_a_m_a [10]3 years ago
6 0
Nam's new balance is $80
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You complete 40% of ur hw problems before dinner what fraction of the problems did u complete before dinner
yuradex [85]
Is there any answer choices? I believe it is 2/5
3 0
3 years ago
How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?
Lunna [17]

Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

an = 100

Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

n = 50

d = 2

l = ?

Find l

l = a1 + (n - 1)*2

l = 1 + 49*2

l = 99

Sum

Sum = (1 + 99)*50/2

Sum = 2500

The difference and answer is 2550 - 2500  = 50

7 0
3 years ago
A sphere has a radius of 3m. Calculate its surface area and round to the nearest hundredth for your final answer.
bonufazy [111]

Answer:

B

Step-by-step explanation:

formula   s =4*pi*r^2

s=4(3.14)(3^2)

s = 12.56(9)s= 113.04

5 0
4 years ago
Consider the following hypothesis test:
Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

H_0: \mu\leq50\\\\H_a:\mu> 50

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0
4 years ago
3.99 4.29 and 2.89 range
oee [108]

Answer:

1.4

Step-by-step explanation:

Sample size: 3

Lowest value: 2.89

Highest value: 4.29

Range: 1.4

formula for calculating the range:

Range = maximum(x_i) - minimum(x_i)

where x_i represents the set of values.

7 0
4 years ago
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