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stellarik [79]
3 years ago
5

"Nucleic acid was isolated by lysing cells in detergent, guanidine isothiocyanate, and DNAse, followed by extraction in an acid

phenol chloroform isoamyl alcohol solution and finally precipitation in ethanol. The concentration of the isolated nucleic acid was measured using SyBr Green II, which yielded fluorescence. When PicoGreen was used to quantitate the nucleic acid, there was no fluorescence in the sample. What type of nucleic acid was isolated?
Chemistry
1 answer:
Romashka [77]3 years ago
8 0

Answer:

RNA

Explanation:

The nucleic isolated was quantified by 2 types of fluorescent dyes, which binds only to specific type of nucleic acid. You can find the information on the specificity of dyes on your labsheet or dye supplier's website. For our dyes, however:

  • SyBr Green II only emits fluorescent light when it binds to RNA or Single Strand DNA
  • PicoGreen only fluoresce when bound to Double Strand DNA

With these information, we know that our nucleic acid is either single strand DNA or RNA, however, it is also mentioned that

"Nucleic acid was isolated by lysing cells in detergent, guanidine isothiocyanate, and DNAse"

DNAse, which is an enzyme that breaks down DNA, destroys any extracted DNA during the process, thus, the only possible nucleic acid we have isolated is RNA

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A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30
Lana71 [14]

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

3 0
3 years ago
What is the volume of an 2.3 solution with 212 grams of calcium chloride dissolved in it
Travka [436]

830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL

I am guessing that the concentration of your solution is 2.3 mol/L.

a) Moles of CaCl2

MM of CaCl2 = 110.98 g/mol

Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)

= 1.910 mol CaCl2

b) Volume of solution

V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution

= 830 mL solution


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