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ololo11 [35]
3 years ago
9

Which best describes electromagnetic waves moving from gamma rays to radio waves along the electromagnetic

Chemistry
2 answers:
Snowcat [4.5K]3 years ago
6 0

Answer:

Wavelength increases, and frequency decreases.

for my lazy friends its letter C

Explanation:

e2021

LiRa [457]3 years ago
5 0

Answer:

c on edg2020

Explanation:

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Will mark brainliest if correct
AURORKA [14]

Answer:

filtration and chromatography

Explanation:

I hope this will help you :-)

7 0
3 years ago
If an atom contains more electrons than protons, it is a action, an anion, or electrically neutral
barxatty [35]
Electrons hold a negative charge, and anion refers to a negatively charged atom.

The answer is anion. Here's a way to help remember:

Cats have paws, and cations are "paws"itive (positive).
6 0
3 years ago
Use the pictures below to answer the following question what type of bond is this
mezya [45]
I literally hate chem but I think it’s ionic, I’m not not completely sure but it kinda sounds about right . Not the best anwser haha hope it kinda helps lol
4 0
2 years ago
Is this correct? please check
Reil [10]

Answer:

A is the correct option

Explanation:

batteries have chemical energy and will convert to electricity and when reached to bulb, it emits light as electromagnetic rays

4 0
2 years ago
0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
erastova [34]

Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

7 0
3 years ago
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