To make it easier, we’ll solve for x, as you do.
To get rid of 3, add 3 to both sides.
5x < 15
Now divide by 5.
x < 3
x is less than 3.
Some integers that satisfy this equation are:
2, 2.9, -10, and anything else below the number 3.
Answer:
True both are 28/15
Step-by-step explanation:
Simplify the following:
5 + 2/3 - (3 + 4/5)
Put 3 + 4/5 over the common denominator 5. 3 + 4/5 = (5×3)/5 + 4/5:
5 + 2/3 - (5×3)/5 + 4/5
5×3 = 15:
5 + 2/3 - (15/5 + 4/5)
15/5 + 4/5 = (15 + 4)/5:
5 + 2/3 - (15 + 4)/5
15 + 4 = 19:
5 + 2/3 - 19/5
Put 5 + 2/3 - 19/5 over the common denominator 15. 5 + 2/3 - 19/5 = (15×5)/15 + (5×2)/15 + (3 (-19))/15:
(15×5)/15 + (5×2)/15 + (3 (-19))/15
15×5 = 75:
75/15 + (5×2)/15 + (3 (-19))/15
5×2 = 10:
75/15 + 10/15 + (3 (-19))/15
3 (-19) = -57:
75/15 + 10/15 + (-57)/15
75/15 + 10/15 - 57/15 = (75 + 10 - 57)/15:
(75 + 10 - 57)/15
| 7 | 5
+ | 1 | 0
| 8 | 5:
(85 - 57)/15
| 7 | 15
| 8 | 5
- | 5 | 7
| 2 | 8:
Answer: 28/15
______________________________________
Simplify the following:
1 + 13/15
Put 1 + 13/15 over the common denominator 15. 1 + 13/15 = 15/15 + 13/15:
15/15 + 13/15
15/15 + 13/15 = (15 + 13)/15:
(15 + 13)/15
| 1 | 5
+ | 1 | 3
| 2 | 8:
Answer: 28/15
1/2 s + 3/4 s + 1/4 s + 4
((2+3+1)/4)s +4
6/4 s + 4
3/2 s + 4
Answer: strong positive correlafion between data plan size 'x' and number of text messages sent 'y'
Step-by-step explanation:
'R' in statistics is used to denote correlation Coefficient. The correlation Coefficient is a value which ranges between -1 to +1. It tells us the level of relationship or correlation which exists between the relative movement of two variables, in this case the relationship between data plan size and the number of text messages sent in the US. R value of 0 depicts that no relationship exists between the two variables, R value closer the R value is to +1 and - 1 depicts the strength of positive and negative correlation of the two variables respectively.
A R value of +0.97 in the context above, depicts a strong positive correlation between data plan size and number of text messages sent in the US. That is large data size usually corresponds to large number of text messages and vice versa.
Answer:
The solution is x = e⁶
Step-by-step explanation:
Hi there!
First, let´s write the equation
ln(x⁶) = 36
Apply logarithm property: ln(xᵃ) = a ln(x)
6 ln(x) = 36
Divide both sides of the equation by 6
ln(x) = 6
Apply e to both sides
e^(ln(x)) = e⁶
x = e⁶
The solution is x = e⁶
Let´s prove why e^(ln(x)) = x
Let´s consider this function:
y = e^(ln(x))
Apply ln to both sides of the equation
ln(y) = ln(e^(ln(x)))
Apply logarithm property: ln(xᵃ) = a ln(x)
ln(y) = ln(x) · ln(e) (ln(e) = 1)
ln(y) = ln(x)
Apply logarithm equality rule: if ln(a) = ln(b) then, a = b
y = x
Since y = e^(ln(x)), then x =e^(ln(x))
Have a nice day!
