Question

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Answer 1

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope (m), use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$        And plug in the two points

(3, -8) = (x₁, y₁)

(6, -4) = (x₂, y₂)

$m=\frac{-4-(-8)}{6-3}$     (two negative signs cancel each other out and become positive)

$m=\frac{-4+8}{6-3}$

$m=\frac{4}{3}$       Now that you know the slope, substitute/plug it into the equation

y = mx + b

$y=\frac{4}{3} x+b$     To find b, plug in either of the points into the equation, then isolate/get the variable "b" by itself. It doesn't matter which. I will use (3, -8)

$-8=\frac{4}{3} (3)+b$

-8 = 4 + b      Subtract 4 on both sides to get "b" by itself

-12 = b

$y=\frac{4}{3}x-12$