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kakasveta [241]
2 years ago
12

Please help as soon as possible

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Answer:

srry but i can't see the graph

Step-by-step explanation:

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consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len
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The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Given that,

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y=2\pir

r=y/2\pi

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x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = \pir² + x²

Substitute the r and x values in above equation,

A(y)= y²/4\pi+(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

y/2\pi + (y-2)/8 =0

y = 2\pi/\pi+4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/\pi+4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

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