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german
3 years ago
13

7 divided by 238 long division show work​

Mathematics
2 answers:
sesenic [268]3 years ago
6 0

7 goes into 238 34 times right you would put 34 under 23 in 238 and 238-34=204 thats how i do it in my school hope it help:)

Aleonysh [2.5K]3 years ago
5 0

Answer:

The solution for long division of <em>238÷7</em> is <em>34 with remainder of 0</em>. You may check the <em>attached figure a</em> to visualize step by step solution of this long division.

Step-by-step explanation:

Please check the attached figure a to visualize step by step solution of this long division.

Here is the step by step solution of 7 divided by 238.

  1. Write the problem in long division format
  2. Divide 23 by 7 to get 3
  3. Multiply the quotient digit (3) by the divisor 7
  4. Subtract 21 from 23
  5. Bring down the next number of the dividend
  6. Divide 28 by 7 to get 4
  7. Multiply the quotient digit (4) by the divisor 7
  8. Subtract 28 from 28
  9. Remainder 0

Hence, The solution for long division of 238÷7 is 34 with remainder of 0. Please see the <em>attached figure</em> <em>a</em> to visualize step by step solution of this long division.

<em>Keywords: long division, divide</em>

<em>Learn more about long division from brainly.com/question/13418916</em>

<em>#learnwithBrainly</em>

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Answer:

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Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

To begin solving this problem we need to first calculate how much money all the supplies will cost. We do this buy adding up the prices of each individual supply. Like so,

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3 years ago
Y=1/6x + 5 what is the answer
kykrilka [37]
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3 years ago
The time for a visitor to read health instructions on a Web site is approximately normally distributed with a mean of 10 minutes
klio [65]

Answer:

a) The mean is 10 and the variance is 0.0625.

b) 0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c) 10.58 minutes.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with a mean of 10 minutes and a standard deviation of 2 minutes.

This means that \mu = 10, \sigma = 2

Suppose 64 visitors independently view the site.

This means that n = 64,  = \frac{2}{\sqrt{64}} = 0.25

a. The expected value and the variance of the mean time of the visitors.

Using the Central Limit Theorem, mean of 10 and variance of (0.25)^2 = 0.0625.

b. The probability that the mean time of the visitors is within 15 seconds of 10 minutes.

15 seconds = 15/60 = 0.25 minutes, so between 9.75 and 10.25 seconds, which is the p-value of Z when X = 10.25 subtracted by the p-value of Z when X = 9.75.

X = 10.25

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{10.25 - 10}{0.25}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 9.75

Z = \frac{X - \mu}{s}

Z = \frac{9.75 - 10}{0.25}

Z = -1

Z = -1 has a p-value of 0.1587.

0.8413 - 0.1587 = 0.6826.

0.6826 = 68.26% probability that the mean time of the visitors is within 15 seconds of 10 minutes.

c. The value exceeded by the mean time of the visitors with probability 0.01.

The 100 - 1 = 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{s}

2.327 = \frac{X - 10}{0.25}

X - 10 = 2.327*0.25

X = 10.58

So 10.58 minutes.

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Step-by-step explanation:

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