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AVprozaik [17]
3 years ago
8

I need help Evaluate functions from their graph

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

g(7)=4

Step-by-step explanation:

We look for where x=7. The way you find the answer is first, find the point (0, 7). Draw a line straight up and down, and see where that line intersects the function. Those intersection points are your answer(there will always be only 1 for a function, but if a graph isn't a function, there might be more than 1).

Using this method here, we see that g(7) intersects our line at (7, 4), so g(7)=4.

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Sonia and sophia are sisters. sonia is 15 years older than sophia. the sum of their ages is 63. how old is sophia?
poizon [28]
Sonia represented by x. Sophia represented by x+15. x+x+15 = 63
2x + 15 =;63
2x = 48
x =;24. Sonia
x+15 = 39. Sophia
6 0
3 years ago
Please help! in a hurry!
Over [174]

Answer: m∠W = 56

because UVWX is a rhombus

=> UV // WX

=> 2y + 2y - 68 = 180

<=> 4y = 248

<=> y = 62

=> m∠W = 2.62 - 68 = 56

Step-by-step explanation:

7 0
3 years ago
You need a total of 50 pounds of two types of ground beef costing $1.25 and $1.60 per pound, respectively. A model for the total
olga nikolaevna [1]

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a mix with a total cost of x=$73.

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6 0
3 years ago
Hich function has a range of {y|y ≤ 5}?
marshall27 [118]

Answer:

f(x)=-(x-4)^{2}+5

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

<u>Verify each case</u>

case A) f(x)=(x-4)^{2}+5

The vertex is the point (4,5)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

y\geq5

case B) f(x)=-(x-4)^{2}+5

The vertex is the point (4,5)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

y\leq 5

case C) f(x)=(x-5)^{2}+4

The vertex is the point (5,4)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

y\geq4

case D) f(x)=-(x-5)^{2}+4

The vertex is the point (5,4)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

y\leq 4

4 0
3 years ago
Evaluate when x = 7 and y = 6 <br> 2x - 3y
IRISSAK [1]
The Answer Here Is -4
5 0
3 years ago
Read 2 more answers
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