The non-rounded sum is 15.579, so you’d round up to 16 since 5 and up rounds up. Hope this helps<3
Answer:
The answer is below
Step-by-step explanation:
a) Given that the number of sample (n) = 300, therefore since n > 30, the distribution of the sample means is going to be normally distributed.
b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.
c) The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:
The answer to #5 is 171
The answer to #6 is -344
Answer:
5/4k^2
Step-by-step explanation:
P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.
We will be using the following property of exponents:
\dfrac{a^x}{a^y}=a^{x-y}.
We have
P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.
Thus, the required product is \dfrac{5}{4k^2}.
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=(new-old)/old *100%
=(90-75)/75 *100%
=20%
<span> hope it helps</span>
