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2 years ago

The expression (y-20)(y5)3 is equivalent to ya. What is the value of a?

Mathematics

1 answer:

Leno4ka [110]2 years ago

5 0

Answer:

y¹⁵-20y¹⁴

Step-by-step explanation:

I'm going to assume that your problem looks like this

$(y-20)(y^5)^3$

$(x^n)^y=x^{n*y}$

which means we have

$(y-20)*y^{15}\\\\y^{16}-20y^{15}=ya\\\\*y^{15}-20y^{14}=a$

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Find the value of r so the line that passes through each pair of points has the given slope.

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Answer:

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Step-by-step explanation:

slope = change in y / change in x, so:

change in y / change in x = 2/3

5 - r / 7 - 1 = 2/3

5 - r / 6 = 2/3

$\frac{5-r}{6}=\frac{2}{3}$

now solve this equation.

first, multiply both sides by 6 to get rid of the fraction:

$5 - r = 4$

subtract 5 from both sides

$-r=-1$

multiply both sides by -1

$r=1$

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Read 2 more answers

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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