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Tresset [83]
3 years ago
14

Triangle QRS has been rotated 90° to create triangle TVU. Using the image below, prove that lines RS and VU have the opposite an

d reciprocal slopes.

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

If the line RS has been rotated 90 degrees, then VU will be perpendicular to RS and the two slopes must be opposite and reciprocal, i.e. product of the two slopes will equal -1.

As a verification, we find the locations of V and U from rotations of R & S.

(actually, the triangle had been rotated -90°, 90 ° clockwise)

Step-by-step explanation:

Slope RS, m1:

Slope VU, m2

Hence m1*m2=1*-1=-1, meaning that m1 and m2 are opposite (in sign) and are reciprocal to each other, as expected

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(2x - 3y)(4x - y) can you help me
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Answer:

<h2>(2x - 3y)(4x - y) = 8x² - 14xy + 3y²</h2>

Step-by-step explanation:

Use FOIL:  <em>(a + b)(c + d) = ac + ad + bc + bd</em>

(2x - 3y)(4x - y) = (2x)(4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)

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<em>combine like terms</em>

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MakcuM [25]

Answer:

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

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Step-by-step explanation:

1) You can buy 4 brownies for $2 each = 2*4 = $8

The rest you can buy cookies = 5 cookies = $5

$8+$5=$13

2) You can buy 5 brownies and 3 cookies = $10+$3 = $13

3) You can buy 3 brownies and 7 cookies = $6+$7=$13

Equation: -

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

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Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

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Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

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Substitute 3 for f(-1)

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Collect Like Terms

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1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

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Collect Like Terms

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k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

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