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kirill115 [55]
3 years ago
6

A parabola opening up or down has vertex (3,-4) and passes through (-4,33/4).write it’s equation in vertex form

Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

y  = 1/4(x - 3)^2 - 4.

Step-by-step explanation:

Vertex form is  y = a(x - j)^2 + k where  (j, k) is the vertex and a is some constant.

Here the vertex is (3 , -4) so we have:

y = a(x - 3)^2 - 4

Now we substitute the point x = -4 and y = 33/4 into the above:

33/4 = a(-4 - 3)^2 - 4

49a = 33/4 + 4 = 49/4

a = 49/4 / 49 = 1/4

So the parabola is 1/4(x - 3)^2 - 4.

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Answer:

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3 years ago
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Put the coordinates of the points to the equations of the functions and check:

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