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oksian1 [2.3K]
3 years ago
5

A line has a slope of -3 and passes through the point (-3, 8). What is the equation of the line?

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

y = -3x - 1

Step-by-step explanation:

don't mind this hebusesjaygsnzoinske

You might be interested in
Simplify
denis23 [38]

Hello!

<u><em>Answer: </em></u>

<u><em>1. =-6</em></u>

<u><em>2. =39</em></u>

<u><em>3. =-603</em></u>

_________________________________________________

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

(3-1)=2

-4*2+2

Then do multiply left to right.

-4*2=-8

Add left to right.

-8+2

8-2=6

*Answer should be have negative sign.*

Answer: → \boxed{=-6}

______________________________________________________

2. 3⋅[(30−8)÷2+2]

Do parenthesis first.

(30-8)=22

22/2+2

Then divide left to right.

22/2=11

Add left to right.

11+2=13

Multiply left to right.

3*13=39

*Answer should be have positive sign.*

Answer: → \boxed{=39}

_____________________________________________________

3. 14(1-23)2+13

Do parenthesis first.

(1-23)=-22

14(-22)*2+13

Then, you multiply left to right.

14(-22)=-308

-308*2=-616

Add/subtract left to right.

-616+13

616-13=603

*The answer must be have a negative sign*

Answer: → \boxed{=-603}

____________________________________________________________

Hope this helps!

Thank you!

Have a great day!

-Charlie

7 0
3 years ago
41/17 rounded to the nearest hendreth
Andrews [41]

Answer:

2.47

Step-by-step explanation:

convert it to a decimal = 2.47058823....

then round that to a nearest hundredth = 2.47

3 0
3 years ago
Read 2 more answers
How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

__

You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

__

Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
3 years ago
......................................................
mafiozo [28]
Hehe lovely what the
8 0
3 years ago
1.A five - layer of cake weighs half a kilogram per layer.In each layer,the cake is decorated with icing which weighs 15g.3 cand
julia-pushkina [17]

Answer:  2.815 kilograms

======================================================

Work Shown:

1 layer = 0.5 kg

5 layers = 5*(0.5 kg) = 2.5 kg

icing = 15 g = 15/1000 = 0.015 kg

1 candle = 100 g = 100/1000 = 0.1 kg

3 candles = 3*(0.1 kg) = 0.3 kg

------------------------

The five layers combine to 2.5 kg. On top of that we have 0.015 kg of icing, and then finally the three candles add 0.3 kg more weight.

The total weight is therefore: 2.5+0.015+0.3 = 2.815 kilograms

3 0
3 years ago
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