Answer:
D. (x-2)(x-4)
Step-by-step explanation:
The graph cross the x-axis in points with x-coordinates of 2 and 4
then 2 and 4 are roots of x² - 6x + 8.
The answer is ( -2 , -1 ) .
Hope it's helped ♥️♥️♥️♥️♥️.
7. X2=25
X=5, x=—5
8. (X—3)2=49
X=10, x=—4
9. X2+3x—28.
X=4, x=—7.
10. 5x2–8=3x.
X=8/5, x=—1
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
<u>6 12.74 12.75 -0.01 0.001</u>
<u>∑ 0.06 0.0173</u>
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.
Answer:
-1.5x + 70
Step-by-step explanation:
Total money he takes while going to the fair = $90
Money he spends to enter the fair = $5
Money he spends on food =$15
Total he spent now is given by
Now, he spend on rides at the fair i.e. 1.50 per ride .
Let the number of rides be x
So, cost incurred on rides = 1.5x
So, the spending money can be expressed as
Now, remaining money left to him after spending on x rides too is
Let f(x) denotes the function used to determine the money he has left over after rides .
So it becomes
f(x) = 70 - 1.50x
f (x) = -1.50x +70
