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Annette [7]
3 years ago
12

-x+ 3y = 14 3x – 3y =-6 How would do in steps ?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

for the first part:

Let's solve for x.

−x+3y=14

Step 1: Add -3y to both sides.

−x+3y+−3y=14+−3y

−x=−3y+14

Step 2: Divide both sides by -1.

−x/−1  =  −3y+14/−1

x=3y−14

Answer:

x=3y−14

Second part:Let's solve for x.

3x−3y=−6

Step 1: Add 3y to both sides.

3x−3y+3y=−6+3y

3x=3y−6

Step 2: Divide both sides by 3.

3x/3= 3y−6/3x=y−2

Answer:

x=y−2

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im fumb so help me with this lol first person to tell me the right anwser will get marked as brainliest​
AnnZ [28]
It is 25 percentage of sqaure
8 0
3 years ago
2x+4y=8
ANTONII [103]

Answer:

(-2, 3) is one of many solutions to the system

Step-by-step explanation:

Let's actually solve the system so that we can compare the result with the given pair (-2, 3):

Multiplying the second equation by -2 results in:

2x + 4y = 8

-2x - 4y  = -8

We see that these equations are identical.  Thus, there are infinitely many solutions.  

1. is true:  (-2, 3) is one of many solutions to the system

The other three possible answers are incorrect.

5 0
3 years ago
George said if 2 and 4 are factors of one number then 8 is a factor of the number is he correct
GREYUIT [131]
No. While this is true in almost all cases, 2 and 4 are both factors of 4, while 8 is not.

For any other number, though, George is correct.
4 0
4 years ago
Find an equation of the vertical line that passes through (x, y) = (14, 15).
WITCHER [35]
X=14 goes through (14,15)
4 0
3 years ago
A rectangular garden has a length of (2y - 4) feet and a width of 4y^2 feet. How do you find the perimeter of the garden
Ber [7]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 {y}^{2}  + 4y - 8}}}}}

Step-by-step explanation:

Given,

Length of a rectangular garden ( l ) = 2y - 4

Width of a rectangular garden ( w ) = 4y²

Perimeter of the garden = ?

<u>Finding</u><u> </u><u>the</u><u> </u><u>perimeter</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having </u><u>length </u><u>of</u><u> </u><u>2</u><u>y</u><u>-</u><u>4</u><u> </u><u>and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>4</u><u>y</u><u>²</u>

\bold{ \boxed{ \sf{perimeter \: of \: a \: rectangle = 2(l + w)}}}

\longrightarrow{ \sf2(2y - 4 + 4 {y}^{2}})

Distribute 2 through the parentheses

\longrightarrow{ \sf{4y - 8 + 8 {y}^{2} }}

Arrange it in standard form

\longrightarrow{ \sf{8 {y}^{2}  + 4y - 8}}

Hope I helped!

Best regards! :D

3 0
4 years ago
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