Answer:
Step-by-step explanation:
Given is a function in f as
![f(x) = log_{10} x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20log_%7B10%7D%20%20x)
We can change base to e for our convenience for finding derivatives
![f(x) = log_{e} x ( log_{10} e)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20log_%7Be%7D%20%20x%20%28%20log_%7B10%7D%20%20e%29)
The second term is a constant with value = 0.434294
So f(x) = 0.434294 ln x
Now differentiate with respect to x two times
I derivative = ![f'(x) = \frac{0.434294}{x} \\f"(x) = - \frac{0.434294}{x^2}](https://tex.z-dn.net/?f=f%27%28x%29%20%20%3D%20%5Cfrac%7B0.434294%7D%7Bx%7D%20%5C%5Cf%22%28x%29%20%3D%20-%20%5Cfrac%7B0.434294%7D%7Bx%5E2%7D)
Note: We can leave as log e to base 10 also without converting into actual values.
Answer:
82.5
Step-by-step explanation:
15 x 11 = 165
165 x 1/2 = 82.5
Answer:
b = 3Vh
Step-by-step explanation:
When they ask to solve for b, you are essentially rearranging the equation so that b is alone on one side.
V = 1/3bh
(V)(3) = (1/3bh)(3)
3V = bh
(3V)/h = (bh)/h
3Vh = b
b = 3Vh
You first combine like terms.
6.51 - 9.32 + h = 1.02
-2.81 + h = 1.02
To isolate the variable you need to add 2.81 to both sides.
h = 3.83
And that is your final answer.
I hope this helps love! :)