Can someone help me with 23?

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

2.5 pounds of apples * $1.20 = $3

He spent total $4.50

So he had to have spent 1.50 on oranges.

So $1.50=$1.20 x where x will be the pound of oranges bought.

1.50/1.20 = 1.25 or 1 1/4 pounds of oranges.

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Fractions equivalent to - 9/16

kiruha [24]

Answer:

Equivalent Fractions for 9/16: There are infinity equivalent fractions to 916. See some examples: 916, 1832, 2748, 3664, 4580, 5496, 63112, 72128, 81144, 90160, 99176, 108192, 117208, 126224, 135240, 144256, 153272, 162288, 171304

Step-by-step explanation:

NOT my answer, got it from g0ogle..

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3 years ago

Find the inverse for each relation: 1. {(1,-2), (2, 3),(3, -3),(4, 2)}

andrey2020 [161]

Answer:

the inverse for each relation:

1. {(1,-2), (2, 3),(3, -3),(4, 2)} is

{(-2,1),(3,2),(-3,3),(2,4)}.

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3 years ago

Which graph represents the function g(x) = 7cosx after a shift of StartFraction 5 pi Over 3 EndFraction units to the right?

pychu [463]

Answer:

It's B, the second graph

Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

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Inga [223]

Answer:

the answer is the second one:

ordered pair (2,-2) ; y-intercept -4

Step-by-step explanation:

hoped that helped

3 0

2 years ago

1.What are the zeros of the polynomial function?

Lorico [155]

Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
_______________

Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
______________

Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
________________

To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9

Well, this would be your answers.

7 0

3 years ago