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IRINA_888 [86]
3 years ago
6

Hunter spent 2/3 of his money

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer: 15

Step-by-step explanation:

10 / (2/3)

10 / 0.66

          15

0.66 | 10.0 \/

       - 9.9

         0.10

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Convert the function into standard form. Show your work. y-2=-3(x+4)^2
Sonja [21]

Answer:

y = -3x² - 24 x + 50

Step-by-step explanation:

y - 2 = - 3(x+4)²

y - 2 = -3(x²+8x+16)

y - 2 = -3x² -24x +48

y = -3x² - 24 x + 50

8 0
3 years ago
Read 2 more answers
Is 10/9 closer to 1,1/2,0
balandron [24]
\dfrac{10}{9}=\dfrac{9+1}{9}=\dfrac{9}{9}+\dfrac{1}{9}=1\dfrac{1}{9} \ \textgreater \  1\\\\therefore\\\\\dfrac{10}{9}\ is\ closter\ to\ 1
5 0
3 years ago
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Identify a possible first step using the elimination method to solve the system and then find the solution to the system.
olchik [2.2K]

Answer:x = 1

y = 1

Step-by-step explanation:

The given system of simultaneous equations is expressed as

3x - 5y = - 2 - - - - - - - - - - - - 1

2x + y = 3 - - - - - - - - - - - - - 2

The first step is to decide on which variable to eliminate. Let us eliminate x. Then we would multiply both rows by numbers which would make the coefficients of x to be equal in both rows.

Multiplying equation 1 by 2 and equation 2 by 3, it becomes

6x - 10y = - 4

6x + 3y = 9

Subtracting, it becomes

- 13y = - 13

y = - 13/- 13 = 1

The next step is to substitute y = 1 into any of the equations to determine x.

Substituting y = 1 into equation 2, it becomes

2x + 1 = 3

2x = 3 - 1 = 2

x = 2/2 = 1

8 0
3 years ago
Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
4 0
3 years ago
Find the GCF ( Greatest Common Factor)<br><br><br>18;45<br><br><br>24;16
nika2105 [10]
18;45 = 9

24;16 = 8

I hope this helps
8 0
3 years ago
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