$\text{The formula of the midpoint of a segment with the end points:}\\\\A(x_A;\ y_A)\ \text{and}\ B(x_B;\ y_B)\\\\M_{AB}=\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

$\text{We have:}\\A(16;\ 5)\to x_A=16;\ y_A=5\\B(28;\ -13)\to x_B=28;\ y_B=-13\\\\\text{substitute:}\\\\M_{AB}=\left(\dfrac{16+28}{2};\ \dfrac{5+(-13)}{2}\right)=\left(\dfrac{44}{2};\ \dfrac{-8}{2}\right)=(22;\ -4)$

7 0

3 years ago

State the slope and the y-intercept for the graph of each equation y= -3/7x–1/7

MaRussiya [10]

Answer: Y-intercept is (0,-1/7) and the slope is -3/7

Step-by-step explanation:

State the slope and the y-intercept for the graph of each

equation y= -3/7x–1/7

To find the y-intercept,

you plug in 0 in for x for y= -3/7x–1/7

y=-3/7(0)-1/7

y=0-1/7

y=-1/7

The y-intercept is (0,-1/7)

To find the slope, you first check that the equation is in the form of y=mx+b

y= -3/7x–1/7 is in the from of y=mx +b.

The m is the slope

hence, in y= -3/7x–1/7 the slope is -3/7

3 0

2 years ago