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saveliy_v [14]
2 years ago
7

Noooooooo Liiiiiiiinnnnnkkkkksssssss... Tanisha and Bess are. Tanisha is half as old Bess. Bess is 6 years older than Tanisha.

Mathematics
1 answer:
goblinko [34]2 years ago
5 0
The answer is D. Tanisha is 6, Bess is 12
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Will give crown to best answer!!!!!!
timurjin [86]
The pair of points defines a line with a slope of -1 is C. (10,3) and (15,-2)
5 0
3 years ago
How can you set notation?<br> {3,8,6} is not a subset of {1,2,3,4,5,6}
8_murik_8 [283]

If A is a subset of B, then all elements from a set A are in a set B.

The number 8 from {3, 8, 6} is not in the set {1, 2, 3, 4, 5, 6}. Therefore {3, 8, 6} is not a subset of {1, 2, 3, 4, 5, 6}.

\{3,\ 8,\ 6\}\not\subset\{1,\ 2,\ 3,\ 4,\ 5,\ 6\}

4 0
3 years ago
It’s 62.40 but I don’t know how to show my work for $52 lunch; 20% tip can someone please help
Ganezh [65]

$52 times 20%

$52 times 20/100

Or

$52 times 0.20

Answer is $10.4

4 0
3 years ago
In △ABC, m∠A=52°, c=11, and m∠B=19°. Find a to the nearest tenth.
Ugo [173]

From the problem we have

In △ABC, m∠A=52°, c=11, and m∠B=19°.

Draw the diagram with the help of given information, (see the attached image)

Now using Sine Law in the Triangle ABC, we can write

Now from Triangle ABC , we can write

\frac{a}{sin52}=\frac{11}{sin109}  \\

Now simplify , we get

\Rightarrow a=\frac{11}{sin109}*sin52\\ \\  \Rightarrow a=\frac{11}{0.9455}*0.7880\\ \\ \Rightarrow a=9.1676 \approx 9.2\\

8 0
3 years ago
Use the continuous compound interest formula to find the indicated value. A=90,000; P=65,452; r=9.1%; t=? t=years (Do not round
Butoxors [25]
\bf \qquad \textit{Simple Interest Earned}\\\\&#10;A=Pe^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &90,000\\&#10;P=\textit{original amount}\to& \$65,452\\&#10;r=rate\to 9.1\%\to \frac{9.1}{100}\to &0.091\\&#10;t=years&#10;\end{cases}

\bf 90000=65452e^{0.091t}\implies \cfrac{90000}{65452}=e^{0.091t}\implies \cfrac{22500}{16363}=e^{0.091t}&#10;\\\\\\&#10;\textit{taking \underline{ln} to both sides}\qquad ln\left( \cfrac{22500}{16363} \right)=ln\left( e^{0.091t} \right)&#10;\\\\\\&#10;ln\left( \cfrac{22500}{16363} \right)=0.091t\implies &#10;\cfrac{ln\left( \frac{22500}{16363} \right)}{0.091}=t
7 0
3 years ago
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