The numbers of students in the 7 schools in a district are given below.

Consider the graph below, and identify the piecewise function that describes it. An image of a graph. Question 12 options: f(x)=

serious [3.7K]

Answer:

20000

Step-by-step explanation:

HOPED THIS HELPED

A brainlyist is always appreciated

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6 0

3 years ago

A deposit of $6,500 was invested and has grown to $8,300 in 5 years. The growth in value was via simple interest, calculated on

bagirrra123 [75]

Answer: 5.5%

Step-by-step explanation:

Since the money invested has grown to $8300 and the principal was $600, this means the interest is:

= $8300 - $6500

= $1800

Simple interest = (Principal × Rate × Time)/100

1800 = (6500 × Rate × 5)/100

Cross multiply

1800 × 100 = 32500 × Rate

Rate = 180000/32500

Rate = 5.5%

5 0

3 years ago

Write 60% as a

Setler79 [48]

Answer:

The answer is three fiths

7 0

3 years ago

The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
$A_{n}=A_{1}+(n-1)d$

$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
d=-2 because the question gives you that

$A_{n}=A_{1}+(n-1)d$
 $A_{29}=47+(29-1)(-2)$
 $A_{29}=47+(28)(-2)$
 $A_{29}=47+-56$
 $A_{29}=-9$

The answer is A. -9.

 

The answer is C. 158

For the second one, it gives you $A_{1}=4$ and $A_{}=18$
You can use this to find d

 $A_{n}=A_{1}+(n-1)d$
 $A_{3}=4+(3-1)d$
 $18=4+(3-1)d$
 $18=4+2d$
 $14=2d$
 $7=d$

Now you can just solve using the equation normally.
 $A_{n}=A_{1}+(n-1)d$
 $A_{23}=4+(23-1)(7)$
 $A_{23}=4+(22)(7)$
 $A_{23}=4+154$
 $A_{23}=158$

The answer is C. 158

8 0

3 years ago

Read 2 more answers

If average of m numbers is n^2 and average of n numbers is m^2 then average of m+n numbers is

kkurt [141]

The sum of the m numbers divided by m (which is the average) equals n^2. Then, the sum of the m numbers equals mn^2.
The sum of the n numbers divided by n (which is the average) equals m^2. Then, the sum of the n numbers equals nm^2.
The average of m+n numbers which is the sum of the m numbers plus the sum of the n numbers divided by (m+n) equals (mn^2+nm^2)/(m+n). This is mn(n+m)/(m+n). Then the factor (m+n) can be ruled out and the result is mn.

4 0

4 years ago