Answer:
a) 

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
b) 

So one deviation below the mean we have: (100-68)/2 = 16%
c) 

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Step-by-step explanation:
For this case we have a random variable with the following parameters:

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.
We want to find the following probability:

We can find the number of deviation from the mean with the z score formula:

And replacing we got


And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
For the second case:


So one deviation below the mean we have: (100-68)/2 = 16%
For the third case:

And replacing we got:


For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Answer:
weight of a water=0.5
spherical ball is filled With water=0.95.
so dear for
22\7*0.5*0.95=1.49
Answer:
1 second
Step-by-step explanation:
h(+-)16+power 2+128+
100%-38%= 62%
To find the decimal of 62%, we will have to divide 62 by 100 to get 0.62.
0.62(800)= 496.
Therefore, 496 people will vote no.
Hope this helps!
Answer:

Step-by-step explanation:

hope this helps
brainliest appreciated
good luck! have a nice day!