The sum of two numbers is zero.
x + y = 0
y = -x
<span>Twice the smaller number subtracted from 3 times the larger number is 10.
Let x represent the larger number and y represent the smaller number.
Twice the smaller number: 2y
3 times the larger number: 3x
</span>Twice the smaller number subtracted from 3 times the larger number is 10.
3x - 2y = 10
-2y = -3x + 10
y = 3/2 x - 5
The equations are:
y = -x
y = 3/2 x - 5
The answer is the first choice.
Well, let's use the Euclidean algorithm:
164 = 4×37 + 16
37 = 2×16 + 5
16 = 3×5 + 1
Then working backwards,
1 = 16 - 3×5
1 = 16 - 3×(37 - 2×16) = 7×16 - 3×37
1 = 7×(164 - 4×37) - 3×37 = 7×164 - 31×37
so that x = 7 and y = -31.
Answer:
12 = x
Step-by-step explanation:
Answer:
57
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
boys: girls : total
3 7 3+7 =10
The total number of students must be a multiple of 10
The class size is between 22 and 34
The only multiple of 10 between those numbers is 30
10,20,<u>30</u>,40
Therefor the class size must be 30
