Answer:
6) 7.85 7) 32.97
Step-by-step explanation:
6) p= 3.14×(5/2)
p= 7.85
7) p= 3.14×10×5
p= 32.97
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
The answer is 51. This is because if you 15 is added then you multiply by the 10
Answer:
1/21
Step-by-step explanation:
2/7 ÷ 6 =
2/7 x 1/6 = 2/42
Simplify by dividing the numerator and denominator by 2
1/21
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-Chetan K
