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Zolol [24]
3 years ago
7

70 points and i’ll give brainliest!! please answer all the questions on the page! must show work and how you got the answer. ple

ase help i’m desperate!!!

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

6. One variable only so pretty straightforward.

length-x+4

width-x

x+x+4=80

2x=76

x=38

x+4=42

answer: length 42cm and width 38cm

7. Another money problem!

n-# of nickels

q-# of quarters

n=3+q

0.05n+0.25q=2.85

Substitution works like a charm!

0.05(3+q)+0.25q=2.85

0.15+0.05q+0.25q=2.85

0.3q=2.7

q=9

n=3+q

n=3+9

n=12

answer: 9 nickels and 12 quarters

8. One variable situation again.

Ann's money-2b+9

Betty's money-b

b+2b+9=60

3b=51

b=17

2b+9=43

answer: Ann has $43 and Betty has $17.

9. # of red m&m's-x+1

# of blue m&m's-x

x+1+x=13

x=6

x+1=7

answer: 6 blue and 7 red m&m's

10. a-number of adult tickets

s-number of student tickets

a+s=785 ----> a=785-s

5a+2s=3280

5(785-s)+2s=3280

-3s=-645

s=215

a+s=785

a+215=785

a=570

answer: 215 children tickets and 570 adult tickets

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Y= 6 + x

Plug the numbers into the equations, for each ordered pair substitute the first number (2) for x and the second number (8) for y...

Do the same thing with (6, 12) and if the number on each side of the equals sign is the same for both ordered pairs then you have the solution.
Hope that helps!
7 0
3 years ago
Whats the solution to this equation? 3x-9=12
Nutka1998 [239]

Answer:

x=7

Step-by-step explanation:

3x-9=12

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6 0
3 years ago
Read 2 more answers
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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A 10-ft-long slide is attached to a deck that is 5 ft high. Find the distance from the bottom of the deck to the bottom of the s
drek231 [11]
Using Pythagorean theorem, the answer should be 8.7ft
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The midpoint of stack A B with bar on top has coordinates of (4, -9). Endpoint A has coordinates (-3, -5). What are the coordina
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I think it's B with the bar on top
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