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Leto [7]
3 years ago
13

A 55m and 35m broad park is surrounded by a 2.5m wide path.

Mathematics
1 answer:
daser333 [38]3 years ago
7 0

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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Answer:

To find the number of calories burned:

Find the Metabolic Equivalent of Task (MET) value of the task.

Calculate the number of calories burned per minute. (MET x body weight in kg x 3.5) / 200.

Multiply the calories burned per minute by the number of minutes of activity.

Now, as per the question, weight is 125 pounds (lb), we will convert the weight in kilogram (kg) which is 1 lb = 0.453 kg, it means 125 lb = 56.7

Now we have to find the MET,

A metabolic equivalent (MET) value is a measurement of the energy cost of a specific physical activity for a specific period of time.

For example. A MET of 1 would be roughly equivalent to a person's energy expenditure from sitting still in a room temperature and not actively digesting food.

As per the Calorie guide value of MET for bowling is 3.9

Now the overall formula is

Calorie Burn (x) = ((MET * body weight in kg * 3.5) / 200) * (Number of minutes) m

x = ((3.9*56.7*3.5)/200) * m

Finally, x = 3.87 m represents the number of calorie burned (x) while bowling m minutes.

8 0
2 years ago
Find the value of x<br><br>m&lt;2 = 9x - 1​
jasenka [17]

Answer: x=9

Step-by-step explanation:

The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.

180=40+40+x

180=80+x

x=100

Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°

180-100=∠2

80°=∠2

The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.

80=9x-1

81=9x

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8 0
2 years ago
A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo
SpyIntel [72]

Answer:

R_{in}=0.2\dfrac{mL}{min}

C(t)=\dfrac{A(t)}{30000}

R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

A(t)=300+2700e^{-\dfrac{t}{1500}},$  A(0)=3000

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

R_{in}=(concentration of chlorine in inflow)(input rate of the water)

=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}

(c) Concentration of chlorine in the pool at time t

Volume of the pool =30,000 Liter

Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}

(d) Rate at which the chlorine is leaving the pool

R_{out}=(concentration of chlorine in outflow)(output rate of the water)

= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

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We then solve the resulting differential equation by separation of variables.

\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}

Taking the integral of both sides

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Recall that when t=0, A(t)=3000 (our initial condition)

3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}

3 0
3 years ago
Alice and Bill are planning to have three children. (Assume that it is equally likely for a boy or a girl to be born.) What is t
zhuklara [117]

Answer:

\frac{1}{8}

Step-by-step explanation:

Alice and Bill  are planning to have three children

We have to find the probability that all three of their children will be girl.

Sample space =S={BBB,BBG,BGB,GBB,GGG,GBG,GGB,BGG}

Total =8

Number of cases in which all three children are girls={GGG}

Probability,P(E)=\frac{number\;of\;favorable\;cases}{Total\;number\;of cases}

Using the formula

Then , the probability that all three of their children will be girls=\frac{1}{8}

6 0
3 years ago
Resuelve el siguiente sistemas de ecuaciones por el método
marishachu [46]

Answer:

x=10 and y=12

Step-by-step explanation:

To solve this quadratic equation we will use two method

1. Elimination method

2. substitution method

first of we use elimination method

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83x-20y=590..........(eq1)

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y will be eliminated by multiplying

(eq1) by 9

(eq2) by 10

which will give

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600x-180y=8160.........(eq4)

see that y has the same value that is (-180y and +180y)

so to eliminate y completely you have to add eq1 and eq2 because if you don't add them together you wont eliminate y

747x-180y=5310

+

600x+180y=8160

=

1347x+0=13470

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x=13470/1347

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eq1

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830-20y=590

like terms

-20y=590-830

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divide both sides with -20

y= -240/-20

y=12

OR

eq2

60x+18y=816..... where x=10

60(10)+18y=816

600+18y=816

like term

18y=816-600

18y=216

y=216/18

y= 12

or eq3 or eq4 you will still get the same answer......

7 0
3 years ago
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