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Damm [24]
3 years ago
10

6. Describe how you would make 250 mL of a 4.5 M silver nitrate solution. SHOW ALL CALCS.

Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer:

Dissolve 190 grams of silver nitrate in 250 mL of water.

Step-by-step explanation:

First, find the moles of AgNO₃ from the volume and concentration.

0.250 L × 4.5 mol/L = 1.125 mol

Next, find the mass of AgNO₃ using the molar mass.

1.125 mol × 170 g/mol = 191.25 g

Rounded to two significant figures, dissolve 190 grams of silver nitrate in 250 mL of water.

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-2/3f=9.2<br> -1/8n = -2/7 <br> 12/20n = -36/44<br> -64.5g = -25.8 <br> -15/28 = -9/10
user100 [1]

Step-by-step explanation:

-2/3f =9.2

cross multiply

27,6= -2f

divide both sides by 2

f = - 13.8

-1/8n = -2/7

cross multiply

-16 = -7n

divide

n = 2.29

12/20n = -36/44

cross multiply

528 = - 720n

divide

n= -0.733

-64.5g = -25.8

divide both sides by -64.5

g = -0.4

the last one has no variable

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So set both equations equal to each other then solve out of x and plug it back into the x equation to find the angles so start with x+5=2x+10 then subtract x from 2x and you will have 1x then subtract 10 from 5 leaving you with negative 5 then x equals negative 5 and then plug it back into the equation so for example 2 times negative 5 equals negative 10 plus positive 10 equals 0 so therefore x equals 0
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4 years ago
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I pretty sure the answer is Nervous

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Answer: it is D)

Step-by-step explanation:

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