Of the cartons produced by a company, 66% have a puncture, 44% have a smashed corner, and 0.50.5% have both a puncture and
1 answer:
Answer:
0.095 or 9.5%
Step-by-step explanation:
Puncture → P(P) = 0.06
Smashed corner → P(S) = 0.04
Puncture and smashed corner → P(P and S) = 0.005
The probability that a randomly selected carton has a puncture or a smashed corner is given by the probability of a puncture, added to the probability of a smashed corner, subtracted by the probability of both:
The probability is 0.095 or 9.5%.
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