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3 years ago

Can someone help me:) thank you!

Mathematics

2 answers:

egoroff_w [7]3 years ago

8 0

Answer:

C) 11

Step-by-step explanation:

It would need to be more than 5....and that is the only one.

aleksandrvk [35]3 years ago

5 0

A hope this helps!!!!!

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Alicia can paint a small room 21 hours faster than Nina aloneness 4 hours slower than Alicia and Nina together. How long will it

Alexeev081 [22]

Answer:

11.413 Hours.

Step-by-step explanation:

Alicia can paint a house in 21 hours; Which means in 1 hour she can paint 1/24 of the house.

Nina can paint the same house in (21+4) hours. Which means in 1 hour she can paint 1/25 of the house.

Together in 1 hour they can paint: 1/21 + 1/25 = 46/525 of the house.

Total Hours for painting the house together will be 525/46 = 11.413 Hours.

7 0

3 years ago

Help me with this in the next 5 hours

zvonat [6]

The answer is D -28

6 0

3 years ago

Read 2 more answers

The functions q and r are defined as follows

kolezko [41]

Answer:

Step-by-step explanation:

So we have the two functions:

$g(x)=-2x-2\text{ and } r(x)=x^2-2$

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

$g(x)=-2x-2\\g(4)=-2(4)-2\\$

Multiply:

$g(4)=(-8)-2$

Subtract:

$g(4)=-10$

Now, substitute this into r(g(4)):

$r(g(4))\\=r(-10)$

And substitute this value into r(x):

$r(-10)=(-10)^2-2$

Square:

$r(-10)=100-2$

Subtract:

$r(-10)=98$

Therefore:

$r(-10)=r(g(4))=98$

3 0

3 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$