The number of mercury atoms required to produce 3.49 L of H2 gas according to the equation would be 1.89 x
From the balanced equation of the reaction:
2 moles of Hg are required to produce 1 mole of the H2 gas.
3.49 L of H2 gas was produced and the density of the gas is 0.0899 g/L
Recall that: density = mass/volume
Mass of the H2 gas = density x volume
= 3.49 x 0.0899
= 0.3138 g of H2 gas
Mole of 0.3138 g of H2 gas = mass/molar mass
= 0.3138/2
= 0.1569 mole
Since the ratio of Hg to H2 according to the equation is 2:1, it means that the mole of Hg is twice the mole of H2.
Thus, mole of Hg = 0.1569 x 2
= 0.3138 mole
According to Avogadro, 1 mole of a substance = 6.022×10^23
0.3138 mole would be:
0.3138 x 6.022 x 10^23
= 1.89 x
More on the number of atoms in molecules can be found here: brainly.com/question/19036641